Collision 1: Bouncing Collision (one moving)
Position-Time |
Net Momentum-Time |
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Velocity-Time |
Momentum-Time |
Calculations:
P-initial = 0.501 kg * 0.4 = 0.2004 kgm/s P-final = 0.501 kg * 0.5 = 0.2505 kgm/s Percent Difference = |0.205-0.2004|/0.2004 = 0.25% |
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Before the collision, cart "a" moves at 0.4 m/s, cart "b" is sitting still. After the collision, cart "a" stops and cart "b" keeps moving at 0.4 meters per second. With a small percent difference, I conclude that the momentum is conserved.
Collision 2: Bouncing Collision (two moving)
Position-Time |
Velocity-Time |
Momentum-TimeCalculations:
P-Initial = 0.501 kg * 0.2 m/s + 0.501 * -0.2 = 0 kg m/s P-Final = 0.501 kg * 0.2m/s + 0.501 * -0.6 = -0.2004 kgm/s Percent Difference = |0- (-0.2004)|/0 = 0% Before the collision, cart "a" moves at 0.2 m/s, cart "b" moves at 0.2 m/s in the opposite direction. After the collision, cart "a" moves at 0.2 m/s and cart "b" moves at 0.6 in the opposite direction. The percent difference was 0, so I can conclude that the momentum was conserved.
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Net Momentum |
Collision 3: Sticky Collision (one moving)
Position-Time |
Velocity-Time |
Momentum-TimeCalculations
P-Initial = 0.501 kg * 0.6 m/s = 0.3006 kgm/s P-Final = (0.501 kg + 0.501 kg )* 0.3 m/s = 0.3006 kgm/s Percent Difference = |0.3006 -0.3006|/0.3006 = 0% |
Net Momentum |
Before the collision, cart "a" moves at 0.6 m/s, cart "b" is sitting still. After the collision, cart "a" and cart "b" keeps moving at 0.3 meters per second. With a small percent difference, I conclude that the momentum is conserved.
Collision 4: Sticky Collision (two moving)
Position-Time |
Velocity-Time |
Momentum-TimeCalculation
P-Initial = 0.501 kg * 0.715 m/s + 0.501 * -0.721 m/s = -0.003 kg m/s P-Final = (0.501 kg + 0.501 kg) * -0.9 m/s = -0.9018 kg m/s Percent Difference = |-0.003 + -0.9018|/-0.003 = 301% |
Net Momentum |
Before the collision, cart "a" moves at 0.715 m/s, cart "b" moves at 0.721 m/s in the opposite direction. After the collision, cart "a" and cart "b" move at 0.9 in the opposite direction. The percent difference was very high so I can conclude that momentum was not conserved in this collision
Collision 5: Explosion Collision
Position-Time |
Velocity-Time |
Momentum-TimeCalculations
P-Initial = 0 kg m/s P-Final = 0.501 kg * 0.3m/s + 0.501 * -0.2 = 0.0501 kgm/s Percent Difference = 0% |
Net Momentum |
Before the collision, cart "a" and cart "b" both are at a stand . After the explosion, cart "a" moves at 0.3 m/s and cart "b" moves at 0.2 in the opposite direction. The percent difference was 0 so I can conclude that the momentum was conserved.
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